lesson

Unit 3 - Derivatives as Local Behavior · AP

Basic Derivative Rules

Derive and use the constant, sum, constant-multiple, and power rules while keeping each shortcut connected to the limit definition.

The derivative definition is the source of every differentiation rule, but re-expanding a difference quotient for every polynomial would be inefficient and obscure the structure we want to see. Basic rules package recurring limit arguments into reliable steps. They are not new definitions of derivative. They are consequences of the same local-rate limit, and they must be used only where their hypotheses fit the expression.

This lesson develops the rules for constants, sums and differences, constant multiples, and powers. These rules cover polynomial functions and many simple models. They do not yet handle a product of two changing factors, a quotient, or one function nested inside another. The next lesson introduces those cases deliberately, especially the Chain Rule, rather than treating every expression as though the power rule applies without thought.

By the end, you should be able to differentiate a polynomial term by term, explain the pattern in the power rule, and use the difference quotient to justify a simple rule. You should also recognize expressions that are not yet eligible for these rules alone. Efficient symbolic work is useful only when it remains attached to the function structure.

Linearity: constants, sums, and constant multiples

The derivative of a constant is zero:

ddx(c)=0.\frac{d}{dx}(c)=0.

A constant function has the same output at every nearby input, so its output change is zero. Its secant and tangent slopes are both zero. For example, a temperature held at 22C22\,\mathrm{^{\circ}C} has rate of change 0Cmin0\,\frac{\mathrm{^{\circ}C}}{\mathrm{min}} with respect to time, even though the temperature value itself is not zero.

Derivatives distribute across addition and subtraction:

ddx[u(x)±v(x)]=u(x)±v(x).\frac{d}{dx}[u(x)\pm v(x)]=u'(x)\pm v'(x).

They also preserve constant multipliers:

ddx[cu(x)]=cu(x).\frac{d}{dx}[c\,u(x)]=c\,u'(x).

Both facts follow because output changes add and constant factors can be pulled outside the difference quotient before taking a limit. A polynomial is a sum of constant multiples of powers, so these rules let us differentiate one term at a time.

A decision map distinguishes constants, sums, constant multiples, and powers before later product and chain rules are needed.

For instance, if p(x)=5x32x+7p(x)=5x^3-2x+7, then differentiate each term: the constant multiple rule gives 15x215x^2 for 5x35x^3, the derivative of 2x-2x is 2-2, and the constant seven becomes zero. Thus p(x)=15x22p'(x)=15x^2-2. Preserve signs and coefficients while differentiating; the derivative of a sum is the sum of derivatives, not a reason to combine unlike terms incorrectly.

The power rule and its visible pattern

For a real exponent nn in a domain where the expression is defined, the power rule is

ddx(xn)=nxn1.\frac{d}{dx}(x^n)=nx^{n-1}.

Read this in two moves: the old exponent becomes a coefficient, then the exponent decreases by one. For x4x^4, the derivative is 4x34x^3. For xx, understood as x1x^1, the derivative is 1x0=11x^0=1. For a reciprocal written as x1x^{-1}, the derivative is x2-x^{-2}, which can be written 1x2-\frac1{x^2} using a horizontal fraction bar.

A power sequence makes the exponent-to-coefficient and exponent-minus-one pattern visible.

Do not misread the rule as “multiply by x.” The exponent changes, but the base stays xx. The derivative of x5x^5 is 5x45x^4, not 5x65x^6 or x4x^4. Checking units and approximate behavior helps: a rapidly growing fifth-power function should have a rate that also grows rapidly for large positive xx, as 5x45x^4 does.

The rule works term by term in a polynomial. If q(x)=3x4x2+6q(x)=3x^4-x^2+6, then

q(x)=12x32x.q'(x)=12x^3-2x.

At x=2x=2, this gives q(2)=92q'(2)=92. That is a slope or rate at input two, not the value q(2)q(2). Keep evaluation as a final step when the question asks for one numerical derivative value.

See a rule emerge from the limit definition

For f(x)=x2f(x)=x^2, start with the definition rather than the shortcut:

f(x)=limh0(x+h)2x2h.f'(x)=\lim_{h\to0}\frac{(x+h)^2-x^2}{h}.

Expanding produces x2+2xh+h2x2x^2+2xh+h^2-x^2, so for nonzero hh the quotient becomes 2x+h2x+h. Its limit as hh approaches zero is 2x2x. This is the power rule for the special case n=2n=2. Notice the order: form a quotient with h0h\ne0, simplify that legitimate expression, then take the limit.

A three-stage diagram expands the difference quotient for x squared, cancels the nonzero h, and then takes the limit.

For a positive integer nn, the expansion of (x+h)n(x+h)^n contains a term nxn1hnx^{n-1}h plus terms with higher powers of hh. Dividing by hh leaves nxn1nx^{n-1} plus terms that contain hh. Those remaining terms approach zero as hh approaches zero. A complete proof uses the binomial theorem, but the mechanism is already visible in the square case: one first-order change survives, while higher-order changes vanish in the local limit.

This derivation is worth remembering because it explains why the power rule has its particular shape. It is not simply a convention. It records the dominant first-order change in xnx^n produced by a small input change. Later, linearization will use this same first-order idea to approximate functions.

Choose a rule that matches the structure

The basic rules apply cleanly to 7x53x2+47x^5-3x^2+4. They do not justify differentiating (x2+1)5(x^2+1)^5 as 5x45x^4, because the base is not xx alone; it is a changing inner function. They also do not justify differentiating x2sinxx^2\sin x by treating it as one power. Those structures need the Chain Rule and Product Rule respectively.

Before differentiating, make a structural pass. Identify whether the expression is a sum of terms, a constant multiple, a power of xx, a product, quotient, or composition. Apply only the rule that matches the outermost structure, and then simplify. This habit prevents most symbolic errors before they occur.

As preparation for the next lesson, differentiate r(x)=4x37x+2r(x)=4x^3-7x+2 and evaluate r(2)r'(2). Then compare the two expressions (3x1)4(3x-1)^4 and x4(3x1)x^4(3x-1). They look related, but one is a composition and the other is a product. Their derivatives require different rules. The next lesson develops those rules from this structural distinction.

Knowledge Map

Where this lesson fits

Prerequisites

Unit 3 - Derivatives as Local BehaviorThe Derivative as a Function

Next lessons

Unit 3 - Derivatives as Local BehaviorProduct, Quotient, and Chain RulesUnit 3 - Derivatives as Local BehaviorImplicit Differentiation and Inverse Functions

Continue exploring

Connections

Related lessons

Unit 3 - Derivatives as Local BehaviorDerivative as Instantaneous Rate and Tangent SlopeUnit 3 - Derivatives as Local BehaviorProduct, Quotient, and Chain Rules

Applications

  • polynomial models
  • motion functions
  • local approximation
  • rate analysis