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Calculus I Supplements · Foundational

Supplement: Derivative Rules and Method Choice

Select and apply derivative rules by reading expression structure, including constant, power, product, quotient, chain, exponential, logarithmic, and trigonometric forms.

Formula reference. Apply the Chain Rule to every differentiable inner function.

Derivative rules

ddx[c]=0,ddx[cf(x)+g(x)]=cf(x)+g(x),ddxxn=nxn1.\frac{d}{dx}[c]=0,\qquad \frac{d}{dx}[cf(x)+g(x)]=cf'(x)+g'(x),\qquad \frac{d}{dx}x^n=nx^{n-1}.

[uv]=uv+uv,[uv]=uvuvv2 (v0),[f(g(x))]=f(g(x))g(x).[uv]'=u'v+uv',\qquad \left[\frac uv\right]'=\frac{u'v-uv'}{v^2}\ (v\ne0),\qquad [f(g(x))]'=f'(g(x))g'(x).

[eu]=ueu,[au]=uaulna,[lnu]=uu,[sinu]=ucosu,[cosu]=usinu.[e^{u}]'=u'e^u,\qquad [a^u]'=u'a^u\ln a,\qquad [\ln|u|]'=\frac{u'}u,\qquad [\sin u]'=u'\cos u,\qquad [\cos u]'=-u'\sin u.

Also: [tanu]=usec2u[\tan u]'=u'\sec^2u where defined. Preserve all original domain restrictions.

Derivative rules are compressed results of the limit definition. They make calculation efficient, but method choice still begins with meaning and structure. Imagine a temperature controller whose output is T(t)T(t). A derivative tells how quickly the temperature is changing at an instant; a correct rule must match how the model was assembled.

Before touching symbols, circle the outermost operation. Is the expression a sum, a product, a quotient, a named function applied to an inner expression, or a composition of several layers? This visual parse prevents the common error of using a rule because a familiar symbol appears somewhere inside. The derivative is determined by the whole expression, not its most noticeable fragment.

Start with linearity and powers

Constants differentiate to zero because they do not change. Sums and constant multiples may be differentiated term by term: ddx[3x47x+2]=12x37\frac{d}{dx}[3x^4-7x+2]=12x^3-7. The Power Rule, ddxxn=nxn1\frac{d}{dx}x^n=nx^{n-1}, applies to a power of the independent variable after algebraic rewriting has exposed it.

For the controller, a background temperature of 2degrees2\,\mathrm{degrees} contributes zero rate, while a term 3t43t^4 contributes 12t3degreess12t^3\,\frac{\mathrm{degrees}}{\mathrm{s}} if time is seconds. Units remind us that differentiating changes the output units. The calculation and interpretation should remain together.

A derivative-rules decision map starts with expression structure rather than a memorized formula.

Follow dependency through products and compositions

For u(x)v(x)u(x)v(x), both factors may change, so (uv)=uv+uv(uv)'=u'v+uv'. For uv\frac{u}{v} with v0v\ne0, the Quotient Rule keeps the denominator squared: (uv)=uvuvv2\left(\frac uv\right)'=\frac{u'v-uv'}{v^2}. These rules are not interchangeable with the Power Rule merely because an exponent occurs somewhere in the expression.

The Chain Rule describes a dependency: if y=f(g(x))y=f(g(x)), then dydx=f(g(x))g(x)\frac{dy}{dx}=f'(g(x))g'(x). Read from outside inward, then multiply by the rate at which the inner quantity changes. If the controller uses T(t)=sin(3t)T(t)=\sin(3t), the sine changes with its angle and the angle changes at 33 radians per second, so T(t)=3cos(3t)T'(t)=3\cos(3t).

An expression tree marks outer and inner functions so the Chain Rule becomes a dependency argument.

Recognize named derivative families

Key formulas include (ex)=ex(e^x)'=e^x, (lnx)=1x(\ln x)'=\frac1x for x>0x>0, (sinx)=cosx(\sin x)'=\cos x, and (cosx)=sinx(\cos x)'=-\sin x. With an inner function, each needs the Chain Rule. The statement ddxln(g(x))=g(x)g(x)\frac{d}{dx}\ln(g(x))=\frac{g'(x)}{g(x)} also requires g(x)>0g(x)>0 in its real-valued form.

After differentiating, test the result against the original model. A positive derivative should match an increasing graph locally, and units should be output units divided by input units. This check catches missing chain factors, reversed quotient terms, and signs that no amount of repeated symbolic copying will reveal.

A derivative sign relationship diagram ties function behavior, first derivative, and second derivative to graphical evidence.

Narrative challenge: diagnose the controller model

The controller model is T(t)=2t2e3tT(t)=2t^2e^{3t}, with tt in seconds. Before looking below, identify the outer structure and differentiate. Explain why differentiating it as 4te3t4te^{3t} is incomplete.

Show a solution path

This is a product of 2t22t^2 and e3te^{3t}. The Product Rule and Chain Rule give T(t)=4te3t+2t2(3e3t)=e3t(4t+6t2)T'(t)=4te^{3t}+2t^2(3e^{3t})=e^{3t}(4t+6t^2). The incomplete answer differentiates the power factor but ignores that the exponential factor also changes with time.

Knowledge Map

Where this lesson fits

Prerequisites

Calculus I SupplementsCalculus Notation and How to Read It

Next lessons

Calculus I SupplementsRules of Integration and Method ChoiceCalculus I SupplementsCommon Antiderivatives

Continue exploring

Connections

Related lessons

Unit 3 - Derivatives as Local BehaviorBasic Derivative RulesUnit 3 - Derivatives as Local BehaviorProduct, Quotient, and Chain Rules

Applications

  • rates
  • optimization
  • model analysis